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Heyo,

I'm having difficulty seeing how these two lines follow. I'm fairly sure I'm being an eejit and the answer's straightforward, but would appreciate a quick explanation of what's going on.

[tex]\frac{1}{2\pi}\int d^3p e^{-i(\emph{p}^2/2m)t} \\ \times e^{i\emph{p.(x-x_0)}} \\

= (\frac{m}{2 \pi it})^{3/2}e^{\frac{im(\emph{x-x_0}^2}{2t}}[/tex]

Thanks in advance.

I'm having difficulty seeing how these two lines follow. I'm fairly sure I'm being an eejit and the answer's straightforward, but would appreciate a quick explanation of what's going on.

[tex]\frac{1}{2\pi}\int d^3p e^{-i(\emph{p}^2/2m)t} \\ \times e^{i\emph{p.(x-x_0)}} \\

= (\frac{m}{2 \pi it})^{3/2}e^{\frac{im(\emph{x-x_0}^2}{2t}}[/tex]

Thanks in advance.

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